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...he function robustm () _that I have created_ to my two matrices, if the difference between the two matrices is less than 0.001, R give me back the last matrix. The code thus created allows me to repeat the process only on the first two matrices: function(x) { for(i in 1:10) repeat { b<-robustm(S_X) b2<-robustm(b) if(abs(b2[i,i]-b[i,i])<=0.001) break } print(b2)} in particular S_X is my matrix number1 (already defined, dim 10*10), b2 is my matrix n.2, if the difference isn't less than my value, I would like reiterate the process using b2 instead S_X and so on... (actually serves t...

Is this how a t hypothesis test is done when I don't have the actual data, but just the summarized statistics: > #Homework 9.2.6 [1] > n<-31 > xbar<-3.10 > s_x<-1.469 > m<-57 > ybar<-2.43 > s_y<-1.35 > s_pooled<- (((n-1)*s_x^2) + ((m-1)*s_y^2)) / (n + m - 2) > s_pooled [1] 1.939521 > t_obs <- (xbar - ybar) / (s_pooled * (sqrt(1/n + 1/m))) > t_obs [1] 1.547951 > qt(c(.025, .975), n+m-2) [1] -1.987934 1.987934 &gt...

..._SetRenderState (0x7fda6e38)->(WINED3DRS_MINTESSELLA TIONLEVEL,1065353216) not handled yet fixme:d3d:IWineD3DDeviceImpl_SetRenderState (0x7fda6e38)->(WINED3DRS_MAXTESSELLA TIONLEVEL,1065353216) not handled yet fixme:d3d:IWineD3DDeviceImpl_SetRenderState (0x7fda6e38)->(WINED3DRS_ADAPTIVETES S_X,0) not handled yet fixme:d3d:IWineD3DDeviceImpl_SetRenderState (0x7fda6e38)->(WINED3DRS_ADAPTIVETES S_Y,0) not handled yet fixme:d3d:IWineD3DDeviceImpl_SetRenderState (0x7fda6e38)->(WINED3DRS_ADAPTIVETES S_Z,1065353216) not handled yet fixme:d3d:IWineD3DDeviceImpl_SetRenderState (0x7fda6e38)-...

Hi, I have 20*60 data matrix (with some NAs) and I wish to perfom a Pearson correlation coefficient matrix as well as simple linear regression equation and coefficient of determination (R2) for every possible combination. Any tip/idea/library/script how do to so. Thanks, As hz -- View this message in context: