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...ze that ++ was available. Is there a comprehensive list somewhere of which operators are available for definition? I searched the R Language manual for ++ but that only came up with a reference to C++ . On 17 Nov 2006 11:38:43 +0100, Peter Dalgaard <p.dalgaard at biostat.ku.dk> wrote: > rfrancois at mango-solutions.com writes: > > > Hi, > > > > You could stack your list in an array and then use apply : > > > > myArray <- array( unlist(lapply(1:3, f) ) , dim =c(2, 3, 3)) > > apply(myArray, c(1,2), sum) > > Or fixup "+" to take more t...

...from the tree itself. Additionally the extension handles filters on the package names. Some examples are given on the homepage but I'm sure there are already regex-friendly people around with more ideas! Comments, Feedbacks, Contributions, ... are always more than welcome. Cheers, Romain rfrancois at mango-solutions.com

...p; sd & 0\% & 25\% & 50\% & 75\% & 100\% \\ \hline 1 & 11493 & 29373.14 & 1777.00 & 3040.00 & 4267 & 6553 & 179774 \\ \hline \end{tabular} \end{center} \end{table} Regards, Liviu ---------- Forwarded message ---------- From: Romain Francois <rfrancois at mango-solutions.com> Date: Dec 5, 2007 2:10 PM Subject: RE: [R] alternatives to latex() or xtable() ? To: Liviu Andronic <landronimirc at gmail.com> You need to look at the digits argument of xtable that would allow you to control this i think. > xtable( numSummary( iris[,1:4]...

Hello everyone, I have several problems with exporting to LaTeX the output of numSummary() from the abind package. > numSummary(finance[,"Cash_flow"], statistics=c("mean", "sd", "quantiles")) mean sd 0% 25% 50% 75% 100% n NA 188070.9 414771.9 -426804 26743 53866 150975.5 1871500 54 4 >

hi all, I'm trying for quite some time to have an x- and y-axis, but no entire box. >plot(..,axes=F) >axis(1) >axis(2) Gives this, but their axes do not go to the origin. Quite a number of people find this gap between the two axes disturbing. Has anyone an idea how to let these axes go to the origin? thank you in advance [[alternative HTML version deleted]]

Dear R Users, I would like to plot three time series on the same graph, two axis on the left and one axis on the right. The time series that I am graphing on the left do not share a similar scale: one has a range of 1:100 and the other a range of 25000:70000. How can I display the tick marks for both on the left hand side without superimposing them, i.e. one set of tick marks in black right

Mango Solutions are pleased to announce the above course in Paris as part of our schedule for Q1 2007. ----------------------------------------------------------------------- Introduction to R and R Programming - 12th February 2008-14th February ----------------------------------------------------------------------- (Please find a french version of this announcement from

Hello all, I just wanted to share a small perl script that generates a dot file from the result of the R profiler. The dot file can than be used to create a graphical display of the profiling. You can save this file in the bin directory of your R installation and then create a graph, for example an SVG by piping the output of the script to dot: $ R CMD Rprof2dot Rprof.out | dot -Tsvg >

Hello, Appending information to the profiler's output seems to generate problems. Here is a small example of code : <code r> require(boot) Rprof( memory.profiling = TRUE) Rprof(NULL) for(i in 1:2){ Rprof( memory.profiling = TRUE, append = TRUE) example(boot) Rprof(NULL) } </code> The problem is that the file Rprof.out contains more than once the header information: $ grep

Hello, What about an `invert` argument in grep, to return elements that are *not* matching a regular expression : R> grep("pink", colors(), invert = TRUE, value = TRUE) would essentially return the same as : R> colors() [ - grep("pink", colors()) ] I'm attaching the files that I modified (against today's tarball) for that purpose. Cheers, Romain --