Displaying 6 results from an estimated 6 matches for "position1".
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2011 Dec 28
2
Gale-Shapley Algorithm for R
...- matrix(0,ncol=n, nrow=m)
for (i in 1:n)
{
step.1[i,][preference.row[i,]==min.n(preference.row[i,],n=1)] <- 1
}
for (i in 1:n){s[i] <- sum(step.1[,i])}
test_s <- s>1
while (any(test_s==TRUE)==TRUE)
{
if (any(test_s==TRUE)==TRUE) {
position1 <- which(s>1)
position2 <- vector('list')
position3 <- vector('list')
position4 <- NULL
position5 <- 1:m
for (k in 1:length(position1)){position2[[k]] <-
which(step.1[,position1[k]]==1)
position3[[k]] <-
which(preference.col[,position1[k]]>min(preference.c...
2011 Sep 12
1
nested anova<-R chrashing
...nt==33,33,ifelse(plant==34,34,ifelse(plant==35,35,ifelse(plant==36,36,
ifelse(plant==37,37,ifelse(plant==38,38,ifelse(plant==39,39,ifelse(plant==40,40,ifelse(plant==41,41,ifelse(plant==42,42,43)))))))))))))))))))))))))))))))))))))))))))
size1<-as.factor(ifelse(size==5,1,ifelse(size==15,2,3)))
position1<-as.factor(ifelse(position==1,1,ifelse(position==2,2,ifelse(position==3,3,
ifelse(position==4,4,ifelse(position==5,5,ifelse(position==6,6,ifelse(position==7,7,
ifelse(position==8,8,ifelse(position==9,9,ifelse(position==10,10,ifelse(position==11,11,ifelse(position==12,12,13)))))))))))))
ANOVA&...
2007 Apr 26
4
select if + other questions
...ems:
1)i cannot get the column names to show up when print to screen
2)I cannot seem to skip variables properly when i choose certain other
variables
3)i cannot get the combination of Select If statements to work to produce
a different table with my new criteria
Here are the variables
PUMFID position1 length 5
PROV position 6 length 2
GRADE position 9 length 2
Y_Q10A position 33 length 1
Y_Q10A has the following 1=yes
2=no
9=skip
all the others have no skipped or missing values
Here is my code:
myfile<-("c:/test2.txt")
myVari...
2007 May 31
0
distribution of peaks in random data results
Dear all,
I have the positions of N points spread through some sequence of length L (L>N), and I would like to know how can do the following:
1- Permute the positions of the N points along the whole sequence.
Assuming a uniform distribution I did: position1 <- runif(N, 1, L)
2- Apply a kernel convolution method to the resulting permuted points profile.
For this I applied the function: d <- density(position1, bw = "sj")
3- Record the heights of all peaks.
For this I used the estimated density values from the output of the density...
2002 Oct 24
0
Here it is
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participants have been receiving an 80% return! The majority have
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refer to title 18, Section 1302 of the Postal and L...
2006 Apr 04
2
ogg + theora + seeking
...the end).
There I don't see any key-frame or "not key-frame" from the position
information.
The header struct I used is
struct oggHeader {
char ogg[5];
char pack_type:1;
char page_type:1;
char last:1;
char reserved:5;
// was: uint64 position;
uint32 position1;
uint32 position2;
uint32 serial;
uint32 pageNo;
uint32 checksum;
} __attribute__ ((packed));
The description only says: devide the position into two fields. is it 2 times
uint32 or some other values?
Thanks in advance
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OggS continued pac...