search for: polhamus

...;s an answer... Can R generate a random variable uniformly distributed on -Inf to Inf? Philosophically this doesn't seem possible, and if not, as I imagine so, is there some sort of generally accepted factor I should be multiplying by a Unif(-1,1) rv to sample from the real line? Thanks, Dan Polhamus [[alternative HTML version deleted]]

...ron Still no luck. Finally, I just set R_LIBS globally (which, was empty) before running the check and the dependencies are then found. Just wanted to be sure I'm not missing something before creating a bug report. This is on Ubuntu 10.04 with R-3.0.2, as root. Many thanks... -- Daniel G Polhamus, PhD Metrum Research Group, LLC [[alternative HTML version deleted]]

...39; variable, for whatever reason R doesn't read it that way. I would be very grateful for any advice on how I can either alter my approach entirely (I am sure there is a far more elegant way to regrid data in R) or a simple fix for this rounding error. Many thanks in advance, Aaron -- Aaron Polhamus <aaronpolhamus@gmail.com> Statistical consultant, Revolution Analytics MSc Applied Statistics, The University of Oxford, 2009 838a NW 52nd St, Seattle, WA 98107 Cell: +1 (206) 380.3948 [[alternative HTML version deleted]]

Dear list, I couldn't find a solution for this problem online, as simple as it seems. Here's the problem: #Construct test dataframe tf <- data.frame(1:3,4:6,c("A","A","A")) #Try the apply function I'm trying to use test <- apply(tf,2,function(x) if(is.numeric(x)) mean(x) else unique(x)[1]) #Look at the output--all columns treated as character

Greetings, My goal is to create a Markov transition matrix (probability of moving from one state to another) with the 'highest traffic' portion of the matrix occupying the top-left section. Consider the following sample: inputData <- c( c(5, 3, 1, 6, 7), c(9, 7, 3, 10, 11), c(1, 2, 3, 4, 5), c(2, 4, 6, 8, 10), c(9, 5, 2, 1, 1) ) MAT <- matrix(inputData,