search for: myboxplot

Displaying 6 results from an estimated 6 matches for "myboxplot".

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2012 Jan 29
1
Modifying whiskers in boxplots?
Hello, I know this has been covered on here before, but as a complete novice, I need a little more guidance. I would like to produce boxplots with the whiskers extending to the 10 and 90th percentiles. I found this code: myboxplot.stats <- function (x, coef = NULL, do.conf = TRUE, do.out = TRUE) { nna <- !is.na(x) n <- sum(nna) stats <- quantile(x, c(.1,.25,.5,.75,.9), na.rm = TRUE) iqr <- diff(stats[c(2, 4)]) out <- x < stats[1] | x > stats[5] conf <- if (do.conf) stats[3] + c(-1....
2008 Aug 21
3
Boxplot 5% and 95% quantile instead of 25% and 75%
Hi, I'm new to the whole R-thing as a replacement for Matlab, not disappointed sofar ;) I found out how to make nice looking boxplots, but i also would like the make a boxplot with 5% and 95% instead of the standard 25 and 75% quantiles. My csv input looks something like: LOCATION FILTER NR DATE VALUE MONTH Peelhorst01 1 14-Jan-94 23.07 1 Peelhorst01 1 28-Jan-94 23.68 1 Peelhorst01 1
2011 Apr 17
3
Box plot with 5th and 95th percentiles instead of 1.5 * IQR: problems implementing an existing solution...
...s instead of at 1.5 * IQR. I have read the relevant documentation, and checked existing mails on this topic. I found a small modification that should work : https://stat.ethz.ch/pipermail/r-help/2001-November/016817.html and tried to implement it. Basically, it says to replace boxplot.stats with: myboxplot.stats <- function (x, coef = NULL, do.conf = TRUE, do.out = TRUE) { nna <- !is.na(x) n <- sum(nna) stats <- quantile(x, c(.05,.25,.5,.75,.95), na.rm = TRUE) iqr <- diff(stats[c(2, 4)]) out <- x < stats[1] | x > stats[5] conf <- if (do.conf) stats[3] + c(-...
2016 Apr 07
1
identifying outliers
Thanks for writing this great piece of code. x = rnorm(100) boxplot(x) # you shouldn't see any outliers here although sometimes yow will # lets add some outliers intentionally x = c(21, 20, 25, x) # now 10, 15 and 20 are outliers myboxplot <- boxplot(x) # now you should see your three outliers myboxplot$out # it will print the values of the outliers How does one amend this code to produce the outliers by a group? All the best, Thomas Subia [[alternative HTML version deleted]]
1999 Jul 06
2
eval(), expression()
Dear R-Users! My aim is to produce boxplots without the outliers included in the plot. I started to write a function that looks something like: myboxplot <-function(x,fa) { bpdata <- boxplot(x~fa,plot=FALSE) bpnames <- names(bpdata) for (JJ in bpnames) { command <- paste("bpdata$",JJ,"$out <- numeric(0)",sep=""); eval(command) } bxp(bpdata) } Obviously this does not work as I intended...
2011 Sep 26
2
Boxplot BUT with Mean, SD, Max & Min ?
People, It appears that there is no way of getting Boxplots to plot using Mean, SD, Max & Min - is there something else that would do what I want? I couldn't find it . . Thanks, Phil. -- Philip Rhoades GPO Box 3411 Sydney NSW 2001 Australia E-mail: phil at pricom.com.au