search for: month1

...Zone.22 Zone.23 Zone.24 -4.416915e+02 4.758455e-01 -1.270986e-04 -5.436199e-01 -1.068809e-01 -1.498580e-01 2.958462e-01 1.316589e-01 -1.328204e-01 -1.605802e-01 5.281869e-03 7.422885e-02 Hours Fishers Month1 Month2 Month3 Month4 Month5 Month6 Month7 Month8 Month9 Month10 9.772076e-02 -2.709955e-03 -1.586887e-01 -1.887837e-02 -5.183241e-03 5.870942e-02 7.075386e-02 2.061223e-02...

If I have data (below) and need some help in figuring out how I can change the values of my date column, so that a year will be from September-August? So the year 1990 = September 89-August 90; 1991 = September 90-August 91, etc... I was trying to use the if() function, but am unable to figure it out. I basically need to change the years associated with September-December to the following

Hi R users, I have a time series variable that is only available at a monthly level for 1 years that I need to decompose to a weekly time series level - can anyone recommend a R function that I can use to decompose this series? eg. if month1 = 1200 I would to decompose so that the sum of the weeks for month1 equals 1200, etc.. Many thanks in advance for any help. -- View this message in context: http://www.nabble.com/Data-decomposition-tp22767614p22767614.html Sent from the R help mailing list archive at Nabble.com.

...quot;0.099","-0.089", "0.005", "-0.0078", "0.67" ) df<- data.frame(comn=comn, mi=mi, x=x) For each company, within a particular month, I would like to compute the standard deviation of x: for example, for abc, I would like to compute the sd of x for month1 (when mi=1) and for month2 (when mi=2). In other languages (Stata for instance), I would create a grouping variable (group comnn and mi) and then, apply the sd function for each group. However, I don't find an elegant way to do the same in R: I was thinking about the following: I could subse...

Dear R users, I cannot display ylab with the following code while trying to stack 7 rows of 3 histograms each. Thanks in advance! par(mfrow=c(7,3)) par(mar=c(2,2,2,2)) par(oma=c(5,5,0,0)) with (newdata <- subset(table, Month1 == "1"), hist(newdata$CarapWid, breaks=5*(0:80), col="gray80", main="All individuals", xlab="", xlim =c(15,85), ylab="April 2007")) - Kumar -- Section of Integrative Biology University of Texas at Austin Austin, Texas 78712, USA [[alternative HT...

...t; > > > I cannot display ylab with the following code while trying to stack 7 > rows > > of 3 histograms each. Thanks in advance! > > > > par(mfrow=c(7,3)) > > par(mar=c(2,2,2,2)) > > par(oma=c(5,5,0,0)) > > > > with (newdata<- subset(table, Month1 == "1"), hist(newdata$CarapWid, > > breaks=5*(0:80), col="gray80", main="All individuals", xlab="", xlim > > =c(15,85), ylab="April 2007")) > > Your code is neither reproducible nor minimal. > And it doesn't look as though i...