Displaying 20 results from an estimated 2279 matches for "mediane".
Did you mean:
median
2011 Jun 28
3
Extract elements from objects in a list
Hi All,
I want to extract elements of elements in a list.
Here's an example of what I mean:
If I create a list:
x <- as.list(100)
for(loop in c(1:100)) {
x[[loop]] <- summary(runif(100))
}
> head(x)
[[1]]
Min. 1st Qu. Median Mean 3rd Qu. Max.
0.02271 0.25260 0.58130 0.52120 0.77270 0.99670
[[2]]
Min. 1st Qu. Median Mean 3rd Qu. Max.
0.006796 0.259700
2020 Sep 21
2
Help with the Error Message in R "Error in 1:nchid : result would be too long a vector"
Hello everyone,
I am using *mlogit* to analyse my choice experiment data. I have *3
alternatives* for each individual and for each individual I have *9
questions*. I have a response from *516 individuals*. So it is a panel of
9*516 observations. I have arranged the data in long format (it contains
100 columns indicating different variables and identifiers).
In mlogit I tried the following
2011 Jun 23
1
else problem
Dear R users,
I have run into a problem using if...else and I hope you can shed some light on it. I am using R version 2.2.0.1.
I have the following data frame:
> head(dat2f)
year tot_km3y
[1,] 1964 0.1876854
[2,] 1965 0.1835116
[3,] 1966 0.1915012
[4,] 1967 0.1869758
[5,] 1968 0.2249865
[6,] 1969 0.1916011
I need to pick out the median year, and since there are an even number of data,
2016 Apr 14
4
Bug in by() function which works for some FUN argument and does not work for others
Dear Sirs,
I am Professor at Indira Gandhi Krishi Vishwavidyalaya, Raipur,
Chhattisgarh, India.
While taking classes, I found the *by() *function producing following error
when I use FUN=mean or median and some other functions, however,
FUN=summary works.
Given below is the output of the example I used on a built-in dataset
"mtcars", along with error message reproduced herewith:
>
2011 Jan 10
2
Step command failing for lm function
Hi,
I have a fairly simple linear regression using the lm function. There
are about 100 variables and 30,000 rows of data. It runs fine and
produces a decent looking R2 value. I'm interested in performing a
stepwise variable selection to see if things can be cleaned up a bit.
Calling the step function returns ONE iteration (all the variables) and
then stops. No errors are reported.
2012 Sep 26
2
specifying arguments in functions and calling functions, within functions
Esteemed R UseRs,
Regarding specifying arguments in functions and calling functions
within functions:
## beginning ##
## some data
ex <- rnorm(10)
ex[5] <- NA
## example function
Scale <- function(x, method=c("mean", "median")) {
scl <- method
scl(x)
}
## both return NA
Scale(ex, method=median)
median(ex, na.rm=FALSE)
## both return the median
Scale(ex,
2005 May 20
1
bootstrapping vectors of unequal length
Dear R Help List,
I have a vector of n and a vector of n-1 and I want to use boot() to
bootstrap the ratio of their respective medians. I want to eventually
use boot.ci() to generate confidence intervals. Because the vectors
are not equal in length, I tried a few things, but have yet to be
successful.
Try 1:
> x <- runif(20)
>
> y <- c(runif(19), NA)
>
> median(x)
[1]
2009 Jul 20
2
calculating median with a condition
Hello,
I am trying to calculate the median of numbers across each row for the data
shown below , with the condition that if the number is negative, that it
should be ignored and the median should be taken of only the positive
numbers.
For eg: data is in Column A,B,C. Column D and E demonstrates what I want to
get as answer
A
B
C
Median
median value
-13.6688115
-32.50914055
2017 Mar 01
1
stats::median
>>>>> Martin Maechler <maechler at stat.math.ethz.ch>
>>>>> on Mon, 27 Feb 2017 10:42:19 +0100 writes:
>>>>> Rob J Hyndman <Rob.Hyndman at monash.edu>
>>>>> on Wed, 15 Feb 2017 21:48:56 +1100 writes:
>> The generic stats::median method is defined as median <-
>> function (x, na.rm = FALSE)
2017 Feb 15
2
stats::median
The generic stats::median method is defined as
median <- function (x, na.rm = FALSE) {UseMethod("median")}
I suggest that this should become
median <- function (x, na.rm = FALSE, ...) {UseMethod("median")}
This would allow additional S3 methods to be developed with additional
arguments.
Currently I have to over-ride this generic definition in the
demography
2004 Jun 24
3
The "median" function in R does not work properly.
Hi,
1.) The "median" function does not work well. Please refer to the data
below (same data is attached as txt-delimited). This is what I try to
do in R:
median ( dataf [2:9] )
I get warning: "needs numeric data"
2.) BUT if apply the median to a single vector:
median ( dataf [,2]] )
then it works:
3.) How come the "median"
2006 Jan 20
3
function for rowMedian?
Hi
is anybody aware of a function to calculate a the median for specified
columns in a dataframe or matrix - so analogous to rowMeans?
Thanks
Max
--
2016 Apr 14
0
Bug in by() function which works for some FUN argument and does not work for others
I think you are not using the best function for what your intentions are.
Try:
> by(data=mtcars, INDICES=list(as.factor(mtcars$am)), FUN=colMeans)
: 0
mpg cyl disp hp drat wt
qsec vs
17.1473684 6.9473684 290.3789474 160.2631579 3.2863158 3.7688947
18.1831579 0.3684211
am gear carb
0.0000000
2015 Jan 28
2
[Q] Get formal arguments of my implemented S4 method
Interrogating some (of my own) code in another package.
>norm.meth <- getMethod("normalize", "MatrixLike")
>message("str(norm.meth)")
>str(norm.meth)
>message("show(norm.meth at .Data)")
>show(norm.meth at .Data)
Last show() displays this:
function (object, ...)
{
.local <- function (object, method = c("median",
2009 Aug 30
2
error with summary(vector)??
Hello,
I get
> summary(E)
level nodes ave_nodes time
Min. : 1 Min. : 1.00 Min. : 10.71 Min. : 0.0000
1st Qu.: 237414 1st Qu.: 2.00 1st Qu.: 19.70 1st Qu.: 0.0100
Median : 749229 Median : 3.00 Median : 27.01 Median : 0.0100
Mean : 767902 Mean : 49.85 Mean : 98.89 Mean : 0.2296
3rd
2009 Aug 21
4
help with median for each row
Hi,
I tried looking through google search on whether there's a way to computer
the median for each row of a nxn matrix and return the medians for each row
for further computation.
And also if the number of columns in the matrix are even, how could I
specify which median to use?
Thank you very much!
--
Edward Chen
[[alternative HTML version deleted]]
2016 Apr 15
4
Bug in by() function which works for some FUN argument and does not work for others
Dear All,
Thanks for your help. However, I would like to draw your attention to the
following:
Actually, I was replicating the Example 2.3, using the dataset
"brainsize.txt" given in Section 2.3.3 ("Summarize by group") at page 55,
of a famous book "R by Example" written by "Jim Albert and Maria Rizzo"
published in Springers (2012) in a Use R! Series. The
2015 Jan 28
2
[Q] Get formal arguments of my implemented S4 method
I'm attempting to reflect the information for use with corresponding
fields in GUI (in a different package), to provide default values,
argname as key for UI label lookups, etc.
So I want something much more like the formals of the implementation:
{
"object",
"method": c("median", "vs", "tukey"),
2007 May 08
3
Median
Hello.
I need calculate the median of several column of a data.frame, in a new
column of this data frame, but the median operator only calculate from a
vector.
I have made a functionc that calculate the median but it is very slow.
Are there any method in any package to calculate this?
Best regards.
Jose Sierra.
A B C
-0.01678042
2004 Mar 11
3
widen the screen place
I have this problem: my screen seems not wide enough in R. My true
computer monitor is very wide, so I wish that I can line up the text
when I stretch it wide. i.e.:
This is typical R returns:
> summary(a)
V1 V2 V3 V4
F:625 Min. :20020103 EMC : 34 Min. : 9300300
L:944 1st Qu.:20020530 BRW : 27 1st Qu.: 9323865