Displaying 1 result from an estimated 1 matches for "meancao".
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macao
2011 Dec 23
1
Long jobs completing without output
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library(arm)
library(foreign)
mlm <- read.dta("../workingdata.dta")
attach(mlm)
gender <- as.factor(stu_gend)
yr <- year - 1998
failure <- (lmer(fail ~
1 + cao + subj1 + subj2 + subj3 + gender + yr + ageentry + as.factor(yrs5)
+ modsize + meancao + depfemr + (1|deptno) + (1|modinst) + (1|ulid) ,
na.action = na.exclude, family = binomial (link="logit")))
display(failure, digits=5, detail=TRUE)
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- output with 10% sample data ---------------------...