search for: maris

Displaying 20 results from an estimated 1148 matches for "maris".

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2008 Nov 08
2
Data Manipulation, add frequency index
Hi, there, I have a simple data manipulation question for you. Thank you for your help! Suppose that I have this data about people appearing in a class Mary Mary Mary Sam Sam John John John John Then I want to find out what exact time(s) the student appears at the moment such as Mary 1 Mary 2 Mary 3 Sam 1 Sam 2 John 1 John 2 John 3 John 4 the fifth row shows tha Sam show the second times
2009 Nov 22
2
Help with indexing
Dear R Helpers, I am missing something very elementary here, and I don't seem to get it from the help pages of the ave, seq and seq_along functions, so I wonder if you could offer a quick help. To use an example from an earlier post on this list, I have a dataframe of this kind: dat = data.frame(name = rep(c("Mary", "Sam", "John"), c(3,2,4))) dat$freq =
2010 Oct 07
3
aggregate text column by a few rows
Hi, R function aggregate can only take summary stats functions, can I aggregate text columns? For example, for the dataframe below, > a <- rbind(data.frame(id=1, name='Tom', hobby='fishing'),data.frame(id=1, name='Tom', hobby='reading'),data.frame(id=2, name='Mary', hobby='reading'),data.frame(id=3, name='John',
2009 Mar 26
2
Analogy for %in% for the whole columns (rather than individual values)
Hello! I have a matrix a with 2 variables (see below) that contain character strings. I need to create a 3rd variable that contains True if the value in column x is equal to the value in column y. The code below does it. a<-data.frame(x=c("john", "mary", "mary", "john"),y=c("mary","mary","john","john"))
2010 Mar 09
5
data frame select max group by like function
Hi, I have a data frame with 3 columns: ID, year and score. How can I select for each unique ID, the year that has the max score? For example, for data frame ID, year, score tom, 1995, 88 rick, 1994, 90 mary, 2000, 97 tom, 1998, 60 mary, 1998,100 I shall have ID, year, score tom, 1995, 88 rick, 1994, 90 mary, 1998,100 Thanks, Richard [[alternative HTML version deleted]]
2011 Jul 27
2
lmtp multiple recipients fail
Hello, I am having a problem with the lmtp delivery of mail addressed to multiple recipients. ?The first recipient receives the mail correctly but the next recipients do not. ?ltmp apparently tries to create a link from the subsequent recipients' mail store to the first recipient mail store and fails. This returns 451 smtp codes to the sender which then resends at some later time. Please see
2007 Mar 26
1
data-frame adding/deleting column
Hallo, I have got an existing data frame and want to add a new column. The existing data frame was created like this: > df <- rbind( c("Fred", "Mary", 4), c("Fred", "Mary", 7), + c("Fred", "Mary", 9), c("Barney", "Liz", 3), + c("Barney", "Liz", 5) ) > df
2010 Apr 02
2
panel data
Hello, I have an unbalanced panel data set that looks like: ID,YEAR,HEIGHT Tom,2007,65 Tom,2008,66 Mary,2007,45 Mary,2008,50 Harry,2007,62 Harry,2008,62 James,2007,68 Jack,2007,70 Jordan,2008,72 That is, James, Jack, and Jordan are missing a YEAR. Is there any command that will "fill in" the missing YEAR such that the end result will be balanced and look like: ID,YEAR,HEIGHT
2010 Jun 08
6
Out of Office
I will be out of the office starting Wed June 9th and returning Wed June 16th. Please contact Mary at mary at accessgate.net cell 407-267-1463 or Jonathan at jsnyder at accessgate.net cell 407-267-0056 or call our main number 888-227-9337.
2013 Apr 30
5
Unaible to create DomU Guest
Hello. First of all I ''m pretty new to Linux and this is my first install of Xen. So don''t mind me wrong if sometimes I don''t know which command is appropriate to fetch results. I''m running a new Debian Squeeze release 2.6.32-5-xen-amd64 with minimal components. I''ve been going through install of Xen as per the documentation for the 4.2.1 release and
2011 Jul 04
1
placing multiple rows in a single row
Dear people from the R help list, I have a question that I can't get my head around to start answering, that is why I am writing to the list. I have data in a format like this (tabs might look weird): John A1 1 0 1 John A2 1 1 1 John A3 1 0 0 Mary A1 1 0 1 Mary A2 0 0 1 Mary A3 1 1 0 Peter A1 1
2007 Oct 09
2
read sas data into R
Hi I am having trouble using read.ssd. Can someone help? The code that I have written is *sashome<-"C:/Mary/Datasets"* *read.ssd(read.ssd(file.path(sashome, "core", "sashelp"), "surv_1v",* *sascmd = file.path(sashome, "sas.exe"))* Here the path that I have given is correct, where the dataset surv_1v.sas7bdat is kept. The message that R gives
2011 Feb 19
0
Samba ACLs and NFS ACLs:Differing results
I have two users on my network, Mary and Bob, who work together in a shared share. They both belong to the group Accounting. Bob is a savvy Linux user who accesses the share via NFS4. Mary toils away using Windows accessing the share via the Samba server. Mary will create a directory on the share and dump a number of files in which Bob and Mary will split the load. Bob, being a LInux user, will
2008 May 25
3
naming components of a list
Hi I have a character vector with thousands of names which looks like this: > V=c("Fred", "Mary", "SAM") > V [1] "Fred" "Mary" "SAM" > class(V) [1] "character" I would like to change it to a list: > L=as.list(V) > L [[1]] [1] "Fred" [[2]] [1] "Mary" [[3]] [1] "SAM" but I need to
2012 Sep 13
1
Parsing "back" to API strcuture
Dear R experts, I'm reading data from an online database via API and it gets delivered in this messy comma separated structure, > RAW.API <-
2005 Aug 11
2
Converting strings with internal delimiters into lists
Hi UserRs, I know that there has to be an easy way to do this in R (probably easy enough that once someone clues me in I'll smack myself on the forehead for not figuring it out myself), but my searches on my own have not yielded any hints. I have many fields in my dataset that participants entered as "free lists" - i.e., the field constitutes a varying number of names each
2007 Jun 28
2
restructuring matrix
Hi all, let's say I have matrix People Desc Value Mary Height 50 Mary Weight 100 Fanny Height 60 Fanny Height 200 Is there a quick way to form the following matrix? People Height Weight Mary 50 100 Fanny 60 200 (Assuming I don't know the length of people/desc and let's say these are characters matrix.. I tried
2013 Apr 13
1
Reshaping Data for bi-partite Network Analysis [SOLVED]
Wow ! so many thanks Arun and Rui works like a charm problem solved 2013/4/13 arun <smartpink111@yahoo.com> > Hi, > Try this; > library(reshape2) > res<-dcast(Input,people~place,value.var="time") > res[is.na(res)]<-0 > res > # people beach home school sport > #1 Joe 5 3 0 1 > #2 Marc 0 4 2 0 > #3 Mary
2013 Apr 13
2
Reshaping Data for bi-partite Network Analysis
Hello I have a dataset of people spending time in places. But most people don't hang out in all the places. it looks like: > Input<-data.frame(people=c("Marc","Marc","Joe","Joe","Joe","Mary"), + place=c("school","home","home","sport","beach","school"), +
2010 Oct 06
3
tapply output
Hello, I am having trouble getting the output from the tapply function formatted so that it can be made into a nice table. Below is my question written in R code. Does anyone have any suggestions? Thank you. Geoff #Input the data; name <- c('Tom', 'Tom', 'Jane', 'Jane', 'Enzo', 'Enzo', 'Mary', 'Mary'); year <- c(2008, 2009,