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...d be really happy if Microsoft showed another facet of their investment into R: Ideally there should be enough staff who can judge and test such bugs and bug fixes? --> I'm BCC'ing this to one place at least. Best, Martin Maechler ETH Zurich > On Thu, Nov 17, 2016 at 2:28 PM, Laviolette, Michael < > Michael.Laviolette at dhhs.nh.gov> wrote: >> The packages "readxl" and "haven" (and possibly others) >> no longer access files on shared network drives. The >> problem appears to be in the normalizePath() >> fun...

...he share, not the highest directory). This can be fixed in the same way Michael found, namely, set the environment variables to use the local mapping rather than the network share. But ideally, the fix would be to treat Windows network paths correctly. Best, Evan On Wed, Nov 30, 2016 at 7:16 AM, Laviolette, Michael < Michael.Laviolette at dhhs.nh.gov> wrote: > In researching another issue, I discovered a workaround: the network drive > folder needs to be mapped to the local PC. > > setwd("//Hzndhhsvf2/data/OCPH/EPI/BHSDM/Group/Michael Laviolette/Stat > tools") > df...

...dplyr_0.5.0 XLConnect_0.2-12 [4] XLConnectJars_0.2-12 ROracle_1.2-1 DBI_0.5-1 loaded via a namespace (and not attached): [1] magrittr_1.5 R6_2.2.0 assertthat_0.1 tools_3.3.2 haven_1.0.0 [6] tibble_1.2 Rcpp_0.12.7 rJava_0.9-8 Please advise. Thanks, Michael Laviolette PhD MPH Public Health Statistician Bureau of Public Health Statistics and Informatics New Hampshire Division of Public Health Services 29 Hazen Drive Concord, NH 03301-6504 Phone: 603-271-5688 Fax: 603-271-7623 Email: Michael.Laviolette at dhhs.nh.gov [[alternative HTML version deleted]]

In researching another issue, I discovered a workaround: the network drive folder needs to be mapped to the local PC. setwd("//Hzndhhsvf2/data/OCPH/EPI/BHSDM/Group/Michael Laviolette/Stat tools") df1 <- readxl::read_excel("addrlist-4-MikeL.xls", 2) # fails, throws same error df2 <- readxl::read_excel("Z:/Stat tools/addrlist-4-MikeL.xls", 2) # works -----Original Message----- From: Martin Maechler [mailto:maech...

...is to say, could it be that it's treating the first path after the single backslash as an actual directory, rather than as the name of the share? -- Evan Cortens, PhD Institutional Analyst - Office of Institutional Analysis Mount Royal University 403-440-6529 On Thu, Nov 17, 2016 at 2:28 PM, Laviolette, Michael < Michael.Laviolette at dhhs.nh.gov> wrote: > The packages "readxl" and "haven" (and possibly others) no longer access > files on shared network drives. The problem appears to be in the > normalizePath() function. The file can be read from a local drive...

...he structure plot(map1) par(new = T) plot(map2) On the screen device, it works fine. When I attempt something like png(file = "map.png") plot(map1) par(new = T) plot(map2) dev.off() only the last map appears, the previous ones having been cleared. Can someone clarify? Thanks, Michael Laviolette PhD MPH New Hampshire Department of Health and Human Services

Hello--I'm doing a simple crosstab using dcast: rawfreq <- dcast(nh11brfs, race3~CHCCOPD, length) with the results race3 Yes No NA 1 White non-Hispanic 446 5473 21 2 Other non-Hispanic 29 211 0 3 Hispanic 6 81 1 4 <NA> 10 83 1 How would I modify this call to exclude all missing values; that is, to obtain race3

My data frame consists of character variables, factors, and proportions, something like c1 <- c("A", "B", "C", "C") c2 <- factor(c(1, 1, 2, 2), labels = c("Y","N")) x <- c(0.5234, 0.6919, 0.2307, 0.1160) y <- c(0.9251, 0.7616, 0.3624, 0.4462) df <- data.frame(c1, c2, x, y) pct <- function(x) round(100*x, 1) I want to

I'm trying to use sqldf to query for the earliest date of a blood test when patients have had multiple tests in a given year. My query looks like this: test11 <- sqldf("select CHILD_ID, min(SAMP_DATE) from lab group by CHILD_ID having extract (year from SAMP_DATE) = 2011") SAMP_DATE has class "date." I get the error

...eights seem to be reversed. Even allowing for that, the deviation between calibrated and raked weights is much more than I expected. I see that in the calibrate function "population" is supposed to be a vector or table, but can't figure out how to adjust. Can you clarify? Thanks. -M. Laviolette satisfy <- c(2,5,2,3,4,3,3,3,4,2,2,3,2,3,4,3,3,2,3,3,4,3,3,3,2, 3,3,3,2,1,4,4,3,3,2,3,4,2,3,3,3,5,3,1,4,3,3,4,4,2, 3,3,3,5,4,4,5,3,4,4,5,3,3,4,3,3,3,3,2,4,4,3,3,4,3, 2,4,4,3,4,4,4,5,3,3,4,4,4,3,2,2,4,3,4,3,4,4,3,3,3, 3,4,4,4,4,3,3,3,3,2,3,3,2...

I'm trying to use the survey package to calculate a risk difference with confidence interval for binge drinking between sexes. Variables are X_RFBING2 (Yes, No) and SEX. Both are factors. I can get the group prevalences easily enough with result <- svyby(~X_RFBING2, ~SEX, la04.svy, svymean, na.rm = TRUE) and then extract components from the svyby object with SE() and coef() to do the