Displaying 2 results from an estimated 2 matches for "lagaoo".
2005 Jun 15
3
Error using newdata argument in survfit
...t the mean of
the covariates, I have been trying to use the newdata argument to survfit
with no success. Here is my model statement, the newdata and the ensuing
error. What am I doing wrong?
> summary(fit)
Call:
coxph(formula = Surv(Start, Stop, Event, type = "counting") ~
Week + LagAOO + Prior.f + cluster(interaction(Station, Year)),
data = data8, method = "breslow", x = T, y = T)
n= 1878
coef exp(coef) se(coef) robust se z p
Week 0.00582 1.01 0.0323 0.0239 0.244 8.1e-01
LagAOO 0.71929 2.05 0.1238 0.1215 5.918 3.3...
2004 Aug 19
0
Clustering and the test for proportional hazards
...st,
Is the test for proportional hazards valid when the model contains a cluster
variable? The output looks strange with the cluster variable.
My intervals are based on calendar time and the clustering variable is
related to the season the event occurs in.
model1<-coxph(Surv(Start,Stop,Event)~LagAOO+I(LagAOO^2)+
FirstSeen+TSLE+strata(CumPOO.rc)+cluster(quarter),data=data8, x=T)
>Cox.zph(model1)
LagAOO 0.209 5.61 0.0179
I(LagAOO^2) -0.209 5.61 0.0179
FirstSeen 0.209 5.61 0.0179
TSLE 0.209 5.61 0.0179
GLOBAL NA 5.61 0.2304
In this example there...