search for: keep1

...s is what I tried : ~$ mkdir -p /tmp/source /tmp/dest ~$ for i in {1..3}; do echo "keep $i"      > /tmp/source/keep$i; done ~$ for i in {4..5}; do echo "to remove $i" > /tmp/source/to-delete-$i; done ~$ rsync -va /tmp/source/ /tmp/dest/ sending incremental file list ./ keep1 keep2 keep3 to-delete-4 to-delete-5 sent 410 bytes  received 114 bytes  1,048.00 bytes/sec total size is 45  speedup is 0.09 ~$ for i in {1..3}; do touch /tmp/source/keep$i; done ~$ cd /tmp/source/ /tmp/source$ find . -name "keep*" | tee /tmp/source/file-list ./keep2 ./keep1 ./keep3...

...n {1..3}; do echo "keep $i"      > /tmp/source/keep$i; done >> >> ~$ for i in {4..5}; do echo "to remove $i" > /tmp/source/to-delete-$i; done >> >> ~$ rsync -va /tmp/source/ /tmp/dest/ >> sending incremental file list >> ./ >> keep1 >> keep2 >> keep3 >> to-delete-4 >> to-delete-5 >> >> sent 410 bytes  received 114 bytes  1,048.00 bytes/sec >> total size is 45  speedup is 0.09 >> >> ~$ for i in {1..3}; do touch /tmp/source/keep$i; done >> >> ~$ cd /tmp/source/...

I was wondering if someone can help me figure out the following: I have two patient datasets, ds1 and ds2. ds1 has fields "patid", "date", and "lab1". ds2 has "patid", "date", and "lab2". I want to find all the patids that have at least 2 dated records for each lab. I started by splitting each dataset by patid, to create ds1.list

...dest > > ~$ for i in {1..3}; do echo "keep $i"      > /tmp/source/keep$i; done > > ~$ for i in {4..5}; do echo "to remove $i" > /tmp/source/to-delete-$i; done > > ~$ rsync -va /tmp/source/ /tmp/dest/ > sending incremental file list > ./ > keep1 > keep2 > keep3 > to-delete-4 > to-delete-5 > > sent 410 bytes  received 114 bytes  1,048.00 bytes/sec > total size is 45  speedup is 0.09 > > ~$ for i in {1..3}; do touch /tmp/source/keep$i; done > > ~$ cd /tmp/source/ > > /tmp/source$ find . -name &qu...