search for: intercet

...es(dat) <- paste(rep(c("a","b"),3:4),c(1:3,1:4),sep="") # In analogy to the ample documentation of lm() : datMean <- cbind(aM=rowMeans(dat[,1:3]),bM=rowMeans(dat[,4:7])) (lmMean <- lm(bM ~ aM,data=as.data.frame(datMean))) # I suppose the estimated parameters (intercet & slope) may be correct but sice the degrees of freedom are not made of means I am convinced they are incorrect and thus any statistics using them will be so, too ... df.residual(lmMean) summary(lmMean) # I also thought about a workaround reorganizing the data into a 'simple' two-colum...

...ron; Michal Kneifl; r-help > Subject: Re: [R] How to fit an linear model withou intercept > > Michael, > Assuming you want a model with an intercept of zero, I think we need to > ask you why you want an intercept of zero. When a "normal" regression > indicates a non-zero intercet, forcing the regression line to have a > zero intercept changes the meaning of the regression coefficients. If > for some reason you want to have a zero intercept, but do not want to > change the meaning of the regression coefficeints, i.e. you still what > to minimize the sum of the sq...

Hello, I wanted to create a histogram, but somehow I got stuck... The interval limits are: x = 1, 2, 3, 3.5, 4.5, 5, 5.5 The interval widths are therefore: 1, 1, 0.5, 1, 0.5, 0.5 Nothing I tried worked... Can anyone help me please? Thanks Tobias -- View this message in context: http://www.nabble.com/Histogram-tf4315900.html#a12288850 Sent from the R help mailing list archive at Nabble.com.