search for: fvec

Displaying 5 results from an estimated 5 matches for "fvec".

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2011 Dec 19
1
None-linear equality constrained optimisation problems
Dear R users, I have a problem. I would like to solve the following: I have pL = 1/(1+e^(-b0+b1)) pM = 1/(1+e^(-b0)) pH = 1/(1+e^(-b0-b1)) My target function is TF= mean(pL,pM,pH) which must equal 0.5% My non-linear constraint is nl.Const = 1-(pM/pH), which must equal 20%, and would like the values of both b0 and b1 where these conditions are met. I have searched widely for an answer,
2011 Mar 15
1
Problem with nls.lm function of minpack.lm package.
...ta and hydraulic conductivity with nls.lm function of minpack.lm package. For the first fit, the parameter estimates keep changing even after 1000 iterations (Th) and I have a following error message for fit of hydraulic conductivity (k); Reason for termination: The cosine of the angle between `fvec' and any column of the Jacobian is at most `gtol' in absolute value. I dont know what I can do for solve my problem Yesterday I asked to Katharine Mullen Here are her aswer Yann P?riard ?tudiant ? la ma?trise en sols et environnement D?partement des sols et de g?nie agroalimentaire...
2010 Feb 16
1
nls.lm & AIC
Hi there, I'm a PhD student investigating growth patterns in fish. I've been using the minpack.lm package to fit extended von Bertalanffy growth models that include explanatory covariates (temperature and density). I found the nls.lm comand a powerful tool to fit models with a lot of parameters. However, in order to select the best model over the possible candidates (without covariates,
2010 Jul 29
7
newton.method
Hi, Is this method broken in R? I am using it to find roots of the following function: f(x) = 2.5*exp(-0.5*(2*0.045 - x)) + 2.5*exp(-0.045) + 2.5*exp(-1.5*x) - 100 It is giving an answer of -38.4762403 which is not even close (f(x) = 2.903809e+25 for x=-38.4762403). The answer should be around 0.01-0.1. This function should converge.. Even for a simple function like f(x) = exp(-x) * x, it gives
2016 Jun 29
2
xapian-letor: FeatureVector discussion
> > > > The approach I was thinking would look something like this: > > * instead of Features, which is really a namespace implemented as a > class, we separate out the calculation of the different features > into distinct subclasses of Feature, whose only job is to calculate > a single feature. Currently the FeatureManager calls these (via >