Displaying 3 results from an estimated 3 matches for "aacbb".
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aabb
2006 Oct 13
5
combinatorics
Hi
How do I generate all ways of ordering sets of indistinguishable items?
suppose I have two A's, two B's and a C.
Then I want
AABBC
AABCB
AACBC
ABABC
. . .snip...
BBAAC
. . .snip...
CBBAA
[there are 5!/(2!*2!) = 30 arrangements. Note AABBC != BBAAC]
How do I do this?
--
Robin Hankin
Uncertainty Analyst
National Oceanography Centre, Southampton
European Way, Southampton SO14
2008 Dec 22
2
How can I avoid nested 'for' loops or quicken the process?
Hi All,
I'm still pretty new to using R - and I was hoping I might be able to get
some advice as to how to use 'apply' or a similar function instead of using
nested for loops.
Right now I have a script which uses nested for loops similar to this:
i <- 1
for(a in Alpha) { for (b in Beta) { for (c in Gamma) { for (d in Delta) {
for (e in Epsilon)
{
Output[i] <-
2008 Dec 29
0
Serial Correlation Test for Short Time Series
...t, clist),1,function(x) paste(x[1],
x[2], x[3], sep=""))
[1] "aabAA" "babAA" "cabAA" "aacAA" "bacAA" "cacAA" "aadAA" "badAA"
"cadAA" "aabBB"
[11] "babBB" "cabBB" "aacBB" "bacBB" "cacBB" "aadBB" "badBB" "cadBB"
> dlist <- list(TRUE,FALSE)
> apply(expand.grid(alist, blist, clist, dlist),1,function(x)
paste(x[1], x[2], x[3], (x[4]), sep=""))[8:12]
[1] "badAATRUE" "cadAATRUE&q...