Displaying 20 results from an estimated 29 matches for "95th".
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5th
2008 Feb 18
2
Custom Plot - means, SD & 5th-95th% (Plotmeans or Boxplot)?
Any help with this problem would be greatly appreciated:
I need to produce a custom plot i haven't come across in R. Basically, I
want to show means, 1st standard deviation and 5th and 95th percentiles
visually, using something resembling a boxplot. Is it possible to completely
customize a boxplot so that it shows means as the bar (instead of, not as
well as medians), standard deviations at the hinges (instead of IQR) and 5th
& 95th percentiles at the brackets? The plotmeans funct...
2011 Apr 17
3
Box plot with 5th and 95th percentiles instead of 1.5 * IQR: problems implementing an existing solution...
Hi all,
I'm just getting started with R and I would appreciate some help. I'm having
trouble creating a boxplot with whiskers at the 95th and 5th percentiles
instead of at 1.5 * IQR. I have read the relevant documentation, and checked
existing mails on this topic. I found a small modification that should work
: https://stat.ethz.ch/pipermail/r-help/2001-November/016817.html and tried
to implement it.
Basically, it says to replace bo...
2006 Jul 24
2
How to obtain 95th percentile of a normal distribution of a continuous variable
Hi,
How do I get R to output the 95% cutoff from a distribution of a continous
variable?
summary() only displays a few statistics....
Thanks!
2013 Aug 29
23
[PATCH] Btrfs: optimize key searches in btrfs_search_slot
...ch of
doing a binary search when the previous binary search returned 0, and
times for the new approach, which directly picks the first item/child
node in the leaf/node.
Current approach:
Count: 5013
Range: 25.000 - 497.000; Mean: 82.767; Median: 64.000; Stddev: 49.972
Percentiles: 90th: 141.000; 95th: 182.000; 99th: 287.000
25.000 - 33.930: 211 ######
33.930 - 45.927: 277 ########
45.927 - 62.045: 1834 #####################################################
62.045 - 83.699: 1203 ###################################
83.699 - 112.789: 609 ##################
112.789 - 151...
2004 Aug 31
4
More efficient matrix computation
I have a 20x3 matrix as follows:
> m <- replicate(3, matrix(rnorm(20),20,1))
I need to compute, say, 95th and 99th percentiles of
each column such that the resulting matrix becomes 2x3
with each row representing the respective percentile.
My "best effort" is to compute one column at a time as
follows:
> quantile(m[,1], c(0.95, 0.99))
To do the same for columns 2 and 3, I would simply
ch...
2012 Nov 08
3
difference percentile R vs SPSS
Dear list,
I am calculating the 95th percentile of a set of values with R and with SPSS
In R:
> normal200<-rnorm(200,0,1)
> qnorm(0.95,mean=mean(normal200),sd=sd(normal200),lower.tail =TRUE)
[1] 1.84191
In SPSS, if I use the same 200 values and select Analyze -> Descriptive Statistics -> Frequencies
and under "...
2010 Apr 05
1
new to R, analysis of latency data
Hi,
I'd like to move from excel to R because our dataset are so large. Here's
what my data looks like:
Transaction Rate Run# Transaction Type Location Latency in
Seconds
10 1 Order
A 0
10 1 Order
B
2010 Dec 17
3
box-and-whisker plots based on summary not data
Hi,
Is it possible to produce box-and-whisker plots given that I have the
median, interquartile and 5/95th centile values, but not the data from
which they come? It seems that it ought to be possible to coerce bxp
to do what I want, but I can't quite see how.
Thanks,
Matthew
--
Matthew Vernon, Research Fellow
Ecology and Epidemiology Group,
University of Warwick
http://blogs.warwick.ac.uk/mcverno...
2001 Nov 25
2
Boxplots using percentiles?
The standard R boxplot appears to use quartiles to determine the height of
the rectangles and a range parameter - RNG - (default=1.5 I think) that
determines the length of the whiskers as <= RNG x Interquartile Range. Is
it possible to instead define the range as extending to the 95th percentile?
If so, how would this be done?
nb, I'm plotting multiple boxplots on a single chart so a function that
applies to multiple series would be useful.
Thanks,
Nick
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2010 Jun 24
4
OT: Bandwidth calculations
Hi,
I know some of you are very experienced as to the working of
networks. I wondered whether there is some accepted way of determining
bandwidth needs based on the network traffic over time. For example,
looking at the figures for the network traffic through the server
interface, we have hourly, daily and monthly figures. If everything
were linear, taking the hourly figure and dividing it by
2004 Aug 10
1
Help with Normal Range Estimation for repated measures
I would be grateful if members of the list could point me in the
direction of any code (preferably in R) that will allow me to estimate
95th percentiles from a set of repeated measurements. For example, we
are interested in a clinical measurement where we have 3 measures for 14
subjects and 2 measurements on 24 subjects and single measurement on 36
subjects. We want to combine these to form a Normal range by using
something that takes a...
2004 Sep 01
1
AW: Looking for help in calculating percentiles
How do I calculate the 95th percentile when I know the 25th, the median and the 75th??
Thanks,
Harmony Tenney
[[alternative HTML version deleted]]
2008 Jan 31
1
how to customize boxplot
...ed. The
problem is that with standard boxplots a too large number of
observations are displayed as outliers. I also tried to display the
log of the observations, but even then there are to may outliers to my
taste. So I'd like to change the standard IQR box to a box which
displays the 5th tothe 95th percentile instead of the standard 25th to
75th percentile.
Is this possible and if so, how? I use both R and Splus, so I'd like
to know for both flavours of S.
Regards,
Cornelis
2008 Aug 02
1
Memory Problems with a Simple Bootstrap - Part II
I have distilled my bootstrap problem down to this bit of code, which
calculates an estimate of the 95th percentile of 7500 random numbers drawn
from a standard normal distribution:
library(boot)
per95 <- function( annual.data, b.index) {
sample.data <- annual.data[b.index]
return(quantile(sample.data,probs=c(0.95))) }
m <- 10000
x <- rnorm(7500,0,1)
B <- boot(data=x,statistic=per...
2012 May 11
1
Strange "Error: subscript out of bounds"
...2, type="l", ylim=c(0,1), xlab=xlab,
axes=FALSE, ylab="Probability", las=1, main=titles[n])
axis(1)
axis(2)
lines(1:5, pred.mat[k+1,], lty=1)
lines(1:5, pred.mat[k+2,], lty=3)
legend("topright", c("avg. player", "5th %-tile player", "95th %-tile
player"), lty=1:3, bty="n")
n<-n+1
}
}
plotProb(q8.pred.mat.v13, c(193, 196, 199, 205, 217,241,289), c(3,3),
q8.titles3, "identification")
[1] "debug"
[1] 193
[1] 1
[1] 1920
Error in print(pred.mat[k, ]) :
error in evaluating the argument 'x...
2006 Aug 10
1
logistic discrimination: which chance performance??
...whether P(obs) is significantly higher than
chance.
I opted for a crude permutation approach: compute P(perm) over 10000 random
permutations of Yobs (i.e., refit the multinom() model 10000 times randomly
permuting Yobs) and consider P(obs) as significantly higher than chance if
higher than the 95th percentile of the P(perm) distribution.
Now, the problem is that the mode of P(perm) is always really close to
P(obs), e.g., if P(obs)=1 (perfect discrimination) also the most likely
P(perm) value is 1!!!
I figured out that this is due to the fact that, with my data, randomly
permuted classifi...
2006 Apr 04
0
Request for guidance
...ll PowerConnect 5224),
four of my own servers (1U Opteron servers, single socket, dual core,
dual NIC), as well 2 servers for 2 friends who will be subleasing
from me. The package includes 6Mbps of bandwidth, burstable to
100Mbps. Bandwidth is tracked with 5-min samples, and as long as my
95th percentile is less than 6Mbps each month, there is no extra
charge for bandwidth.
I would like to use tc bandwidth shaping so that I can
1) ensure that I never have to pay for extra bandwidth in any month
2) be able to guarantee all servers a predefined minimum slice of
bandwidth
I am a softw...
2018 Jan 31
1
Problems with "predict" function
Hello,
I am synthesising some sales data over a twelve month period, and then trying to
use the "predict" function, firstly to generate a thirteenth month forecast with
upper and lower 95% confidence limits. So far so good
But what I then want to do is add the upper sales value at the 95th confidence
limit to the vector of thirteen months and their respective sales to create a
fourteenth month with a predicted sale and the 95% upper confidence limit for
this, and so on The idea being to create a "trumpet" of extreme posistions
But I keep getting instead of one line of pre...
2007 Nov 22
3
question about extreme value distribution
Hello,
I have a question about using extreme
value distribution in R.
I have two variables, X and Y, and have pairs
of points (X1,Y1),(X2,Y2), (X3,Y3) etc.
When I plot X against Y, it looks
like the maximum value of Y (for a particular X) is
correlated with X.
Indeed, when I bin the data by X-value into
equally sized bins, and test whether the maximum
value of Y for a bin is correlated with
2011 Nov 11
8
Help
Dear Contributors
I would like to perform this operation using a loop, instead of repeating
the same operation many times.
The numbers from 1 to 4 related to different groups that are in the
database and for which I have the same data.
x<-c(1,3,7)
datiP1 <- datiP[datiP$city ==1,x];
datiP2 <- datiP[datiP$city ==2,x];
datiP3 <- datiP[datiP$city ==3,x]
datiP4 <-